9(2s+3)+2=11(s-5)

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Solution for 9(2s+3)+2=11(s-5) equation: 



9(2s+3)+2=11(s-5)

We move all terms to the left:

9(2s+3)+2-(11(s-5))=0

We multiply parentheses

18s-(11(s-5))+27+2=0



We calculate terms in parentheses: -(11(s-5)), so:

11(s-5)

We multiply parentheses

11s-55

Back to the equation:

-(11s-55)



We add all the numbers together, and all the variables

18s-(11s-55)+29=0

We get rid of parentheses

18s-11s+55+29=0

We add all the numbers together, and all the variables

7s+84=0

We move all terms containing s to the left, all other terms to the right

7s=-84

s=-84/7

s=-12

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