9(2t+1)-13=t-(t+3)

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Solution for 9(2t+1)-13=t-(t+3) equation: 



9(2t+1)-13=t-(t+3)

We move all terms to the left:

9(2t+1)-13-(t-(t+3))=0

We multiply parentheses

18t-(t-(t+3))+9-13=0



We calculate terms in parentheses: -(t-(t+3)), so:

t-(t+3)

We get rid of parentheses

t-t-3

We add all the numbers together, and all the variables

-3

Back to the equation:

-(-3)



We add all the numbers together, and all the variables

18t-1=0

We move all terms containing t to the left, all other terms to the right

18t=1

t=1/18

t=1/18

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