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9(2x+32=9(2/9)x
We move all terms to the left:
9(2x+32-(9(2/9)x)=0
Domain of the equation: 9)x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
9(2x+32-(9(+2/9)x)=0
We multiply all the terms by the denominator
9(2x+32-(9(+2=0
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