9(2x+5)+23x=-8x+3(5x-2)+3+6X

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Solution for 9(2x+5)+23x=-8x+3(5x-2)+3+6X equation: 



9(2x+5)+23x=-8x+3(5x-2)+3+6x

We move all terms to the left:

9(2x+5)+23x-(-8x+3(5x-2)+3+6x)=0

We add all the numbers together, and all the variables

23x+9(2x+5)-(-8x+3(5x-2)+3+6x)=0

We multiply parentheses

23x+18x-(-8x+3(5x-2)+3+6x)+45=0



We calculate terms in parentheses: -(-8x+3(5x-2)+3+6x), so:

-8x+3(5x-2)+3+6x

determiningTheFunctionDomain
-8x+3(5x-2)+6x+3

We add all the numbers together, and all the variables

-2x+3(5x-2)+3

We multiply parentheses

-2x+15x-6+3

We add all the numbers together, and all the variables

13x-3

Back to the equation:

-(13x-3)



We add all the numbers together, and all the variables

41x-(13x-3)+45=0

We get rid of parentheses

41x-13x+3+45=0

We add all the numbers together, and all the variables

28x+48=0

We move all terms containing x to the left, all other terms to the right

28x=-48

x=-48/28

x=-1+5/7

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