9(2x+7)=4(3x-9)+33

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Solution for 9(2x+7)=4(3x-9)+33 equation: 



9(2x+7)=4(3x-9)+33

We move all terms to the left:

9(2x+7)-(4(3x-9)+33)=0

We multiply parentheses

18x-(4(3x-9)+33)+63=0



We calculate terms in parentheses: -(4(3x-9)+33), so:

4(3x-9)+33

We multiply parentheses

12x-36+33

We add all the numbers together, and all the variables

12x-3

Back to the equation:

-(12x-3)



We get rid of parentheses

18x-12x+3+63=0

We add all the numbers together, and all the variables

6x+66=0

We move all terms containing x to the left, all other terms to the right

6x=-66

x=-66/6

x=-11

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