9(2x-3)=7(x-3)+7

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Solution for 9(2x-3)=7(x-3)+7 equation: 



9(2x-3)=7(x-3)+7

We move all terms to the left:

9(2x-3)-(7(x-3)+7)=0

We multiply parentheses

18x-(7(x-3)+7)-27=0



We calculate terms in parentheses: -(7(x-3)+7), so:

7(x-3)+7

We multiply parentheses

7x-21+7

We add all the numbers together, and all the variables

7x-14

Back to the equation:

-(7x-14)



We get rid of parentheses

18x-7x+14-27=0

We add all the numbers together, and all the variables

11x-13=0

We move all terms containing x to the left, all other terms to the right

11x=13

x=13/11

x=1+2/11

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