9(2x-3)=7(x-3)+7

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Solution for 9(2x-3)=7(x-3)+7 equation:



9(2x-3)=7(x-3)+7
We move all terms to the left:
9(2x-3)-(7(x-3)+7)=0
We multiply parentheses
18x-(7(x-3)+7)-27=0
We calculate terms in parentheses: -(7(x-3)+7), so:
7(x-3)+7
We multiply parentheses
7x-21+7
We add all the numbers together, and all the variables
7x-14
Back to the equation:
-(7x-14)
We get rid of parentheses
18x-7x+14-27=0
We add all the numbers together, and all the variables
11x-13=0
We move all terms containing x to the left, all other terms to the right
11x=13
x=13/11
x=1+2/11

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