9(2x-3x)-29=8x-(x-23)

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Solution for 9(2x-3x)-29=8x-(x-23) equation: 



9(2x-3x)-29=8x-(x-23)

We move all terms to the left:

9(2x-3x)-29-(8x-(x-23))=0

We add all the numbers together, and all the variables

9(-1x)-(8x-(x-23))-29=0

We multiply parentheses

-9x-(8x-(x-23))-29=0



We calculate terms in parentheses: -(8x-(x-23)), so:

8x-(x-23)

We get rid of parentheses

8x-x+23

We add all the numbers together, and all the variables

7x+23

Back to the equation:

-(7x+23)



We get rid of parentheses

-9x-7x-23-29=0

We add all the numbers together, and all the variables

-16x-52=0

We move all terms containing x to the left, all other terms to the right

-16x=52

x=52/-16

x=-3+1/4

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