9(2x-5)-3(5-2x)=4(10-3x)+2(4x-1)

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Solution for 9(2x-5)-3(5-2x)=4(10-3x)+2(4x-1) equation: 



9(2x-5)-3(5-2x)=4(10-3x)+2(4x-1)

We move all terms to the left:

9(2x-5)-3(5-2x)-(4(10-3x)+2(4x-1))=0

We add all the numbers together, and all the variables

9(2x-5)-3(-2x+5)-(4(-3x+10)+2(4x-1))=0

We multiply parentheses

18x+6x-(4(-3x+10)+2(4x-1))-45-15=0



We calculate terms in parentheses: -(4(-3x+10)+2(4x-1)), so:

4(-3x+10)+2(4x-1)

We multiply parentheses

-12x+8x+40-2

We add all the numbers together, and all the variables

-4x+38

Back to the equation:

-(-4x+38)



We add all the numbers together, and all the variables

24x-(-4x+38)-60=0

We get rid of parentheses

24x+4x-38-60=0

We add all the numbers together, and all the variables

28x-98=0

We move all terms containing x to the left, all other terms to the right

28x=98

x=98/28

x=3+1/2

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