9(2x-5)-3(6x+1)=-48

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Solution for 9(2x-5)-3(6x+1)=-48 equation: 



9(2x-5)-3(6x+1)=-48

We move all terms to the left:

9(2x-5)-3(6x+1)-(-48)=0

We add all the numbers together, and all the variables

9(2x-5)-3(6x+1)+48=0

We multiply parentheses

18x-18x-45-3+48=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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