9(2y-4)=6(y+2)

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Solution for 9(2y-4)=6(y+2) equation: 



9(2y-4)=6(y+2)

We move all terms to the left:

9(2y-4)-(6(y+2))=0

We multiply parentheses

18y-(6(y+2))-36=0



We calculate terms in parentheses: -(6(y+2)), so:

6(y+2)

We multiply parentheses

6y+12

Back to the equation:

-(6y+12)



We get rid of parentheses

18y-6y-12-36=0

We add all the numbers together, and all the variables

12y-48=0

We move all terms containing y to the left, all other terms to the right

12y=48

y=48/12

y=4

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