9(2z+3)-5=-(z-3)

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Solution for 9(2z+3)-5=-(z-3) equation: 



9(2z+3)-5=-(z-3)

We move all terms to the left:

9(2z+3)-5-(-(z-3))=0

We multiply parentheses

18z-(-(z-3))+27-5=0



We calculate terms in parentheses: -(-(z-3)), so:

-(z-3)

We get rid of parentheses

-z+3

We add all the numbers together, and all the variables

-1z+3

Back to the equation:

-(-1z+3)



We add all the numbers together, and all the variables

18z-(-1z+3)+22=0

We get rid of parentheses

18z+1z-3+22=0

We add all the numbers together, and all the variables

19z+19=0

We move all terms containing z to the left, all other terms to the right

19z=-19

z=-19/19

z=-1

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