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9(3+1x)=6(2x-1)
We move all terms to the left:
9(3+1x)-(6(2x-1))=0
We add all the numbers together, and all the variables
9(x+3)-(6(2x-1))=0
We multiply parentheses
9x-(6(2x-1))+27=0
We calculate terms in parentheses: -(6(2x-1)), so:We get rid of parentheses
6(2x-1)
We multiply parentheses
12x-6
Back to the equation:
-(12x-6)
9x-12x+6+27=0
We add all the numbers together, and all the variables
-3x+33=0
We move all terms containing x to the left, all other terms to the right
-3x=-33
x=-33/-3
x=+11
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