9(3+5)=4(b+3)

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Solution for 9(3+5)=4(b+3) equation: 



9(3+5)=4(b+3)

We move all terms to the left:

9(3+5)-(4(b+3))=0

We add all the numbers together, and all the variables

-(4(b+3))+98=0



We calculate terms in parentheses: -(4(b+3)), so:

4(b+3)

We multiply parentheses

4b+12

Back to the equation:

-(4b+12)



We get rid of parentheses

-4b-12+98=0

We add all the numbers together, and all the variables

-4b+86=0

We move all terms containing b to the left, all other terms to the right

-4b=-86

b=-86/-4

b=21+1/2

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