9(3+b)=4(b+14)

Solution for 9(3+b)=4(b+14) equation:

9(3+b)=4(b+14)

We move all terms to the left:

9(3+b)-(4(b+14))=0

We add all the numbers together, and all the variables

9(b+3)-(4(b+14))=0

We multiply parentheses

9b-(4(b+14))+27=0


We calculate terms in parentheses: -(4(b+14)), so:

4(b+14)

We multiply parentheses

4b+56

Back to the equation:

-(4b+56)


We get rid of parentheses

9b-4b-56+27=0

We add all the numbers together, and all the variables

5b-29=0

We move all terms containing b to the left, all other terms to the right

5b=29

b=29/5

b=5+4/5