9(3+c)=(3+c)

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Solution for 9(3+c)=(3+c) equation: 



9(3+c)=(3+c)

We move all terms to the left:

9(3+c)-((3+c))=0

We add all the numbers together, and all the variables

9(c+3)-((c+3))=0

We multiply parentheses

9c-((c+3))+27=0



We calculate terms in parentheses: -((c+3)), so:

(c+3)

We get rid of parentheses

c+3

Back to the equation:

-(c+3)



We get rid of parentheses

9c-c-3+27=0

We add all the numbers together, and all the variables

8c+24=0

We move all terms containing c to the left, all other terms to the right

8c=-24

c=-24/8

c=-3

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