9(3+c)=4(3-c)

Solution for 9(3+c)=4(3-c) equation:

9(3+c)=4(3-c)

We move all terms to the left:

9(3+c)-(4(3-c))=0

We add all the numbers together, and all the variables

9(c+3)-(4(-1c+3))=0

We multiply parentheses

9c-(4(-1c+3))+27=0


We calculate terms in parentheses: -(4(-1c+3)), so:

4(-1c+3)

We multiply parentheses

-4c+12

Back to the equation:

-(-4c+12)


We get rid of parentheses

9c+4c-12+27=0

We add all the numbers together, and all the variables

13c+15=0

We move all terms containing c to the left, all other terms to the right

13c=-15

c=-15/13

c=-1+2/13