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9(3+x)=6(2x)
We move all terms to the left:
9(3+x)-(6(2x))=0
determiningTheFunctionDomain 9(3+x)-62x=0
We add all the numbers together, and all the variables
9(x+3)-62x=0
We add all the numbers together, and all the variables
-62x+9(x+3)=0
We multiply parentheses
-62x+9x+27=0
We add all the numbers together, and all the variables
-53x+27=0
We move all terms containing x to the left, all other terms to the right
-53x=-27
x=-27/-53
x=27/53
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