9(3-2x)=2(10-8x)+1

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Solution for 9(3-2x)=2(10-8x)+1 equation: 



9(3-2x)=2(10-8x)+1

We move all terms to the left:

9(3-2x)-(2(10-8x)+1)=0

We add all the numbers together, and all the variables

9(-2x+3)-(2(-8x+10)+1)=0

We multiply parentheses

-18x-(2(-8x+10)+1)+27=0



We calculate terms in parentheses: -(2(-8x+10)+1), so:

2(-8x+10)+1

We multiply parentheses

-16x+20+1

We add all the numbers together, and all the variables

-16x+21

Back to the equation:

-(-16x+21)



We get rid of parentheses

-18x+16x-21+27=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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