9(3-2x)=2(10-8x)x=

Solution for 9(3-2x)=2(10-8x)x= equation:

9(3-2x)=2(10-8x)x=

We move all terms to the left:

9(3-2x)-(2(10-8x)x)=0

We add all the numbers together, and all the variables

9(-2x+3)-(2(-8x+10)x)=0

We multiply parentheses

-18x-(2(-8x+10)x)+27=0


We calculate terms in parentheses: -(2(-8x+10)x), so:

2(-8x+10)x

We multiply parentheses

-16x^2+20x

Back to the equation:

-(-16x^2+20x)


We get rid of parentheses

16x^2-20x-18x+27=0

We add all the numbers together, and all the variables

16x^2-38x+27=0

a = 16; b = -38; c = +27;
Δ = b2-4ac
Δ = -382-4·16·27
Δ = -284
Delta is less than zero, so there is no solution for the equation