9(3k-5)=12(3k-1)-15

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Solution for 9(3k-5)=12(3k-1)-15 equation: 



9(3k-5)=12(3k-1)-15

We move all terms to the left:

9(3k-5)-(12(3k-1)-15)=0

We multiply parentheses

27k-(12(3k-1)-15)-45=0



We calculate terms in parentheses: -(12(3k-1)-15), so:

12(3k-1)-15

We multiply parentheses

36k-12-15

We add all the numbers together, and all the variables

36k-27

Back to the equation:

-(36k-27)



We get rid of parentheses

27k-36k+27-45=0

We add all the numbers together, and all the variables

-9k-18=0

We move all terms containing k to the left, all other terms to the right

-9k=18

k=18/-9

k=-2

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