9(3l-4)+7=2(l-4)

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Solution for 9(3l-4)+7=2(l-4) equation: 



9(3l-4)+7=2(l-4)

We move all terms to the left:

9(3l-4)+7-(2(l-4))=0

We multiply parentheses

27l-(2(l-4))-36+7=0



We calculate terms in parentheses: -(2(l-4)), so:

2(l-4)

We multiply parentheses

2l-8

Back to the equation:

-(2l-8)



We add all the numbers together, and all the variables

27l-(2l-8)-29=0

We get rid of parentheses

27l-2l+8-29=0

We add all the numbers together, and all the variables

25l-21=0

We move all terms containing l to the left, all other terms to the right

25l=21

l=21/25

l=21/25

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