9(3n+5)=9(7n+4)+7

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Solution for 9(3n+5)=9(7n+4)+7 equation: 



9(3n+5)=9(7n+4)+7

We move all terms to the left:

9(3n+5)-(9(7n+4)+7)=0

We multiply parentheses

27n-(9(7n+4)+7)+45=0



We calculate terms in parentheses: -(9(7n+4)+7), so:

9(7n+4)+7

We multiply parentheses

63n+36+7

We add all the numbers together, and all the variables

63n+43

Back to the equation:

-(63n+43)



We get rid of parentheses

27n-63n-43+45=0

We add all the numbers together, and all the variables

-36n+2=0

We move all terms containing n to the left, all other terms to the right

-36n=-2

n=-2/-36

n=1/18

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