9(3x+4)-2x-5=5(62+7x)+4(6x-3)

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Solution for 9(3x+4)-2x-5=5(62+7x)+4(6x-3) equation: 



9(3x+4)-2x-5=5(62+7x)+4(6x-3)

We move all terms to the left:

9(3x+4)-2x-5-(5(62+7x)+4(6x-3))=0

We add all the numbers together, and all the variables

9(3x+4)-2x-(5(7x+62)+4(6x-3))-5=0

We add all the numbers together, and all the variables

-2x+9(3x+4)-(5(7x+62)+4(6x-3))-5=0

We multiply parentheses

-2x+27x-(5(7x+62)+4(6x-3))+36-5=0



We calculate terms in parentheses: -(5(7x+62)+4(6x-3)), so:

5(7x+62)+4(6x-3)

We multiply parentheses

35x+24x+310-12

We add all the numbers together, and all the variables

59x+298

Back to the equation:

-(59x+298)



We add all the numbers together, and all the variables

25x-(59x+298)+31=0

We get rid of parentheses

25x-59x-298+31=0

We add all the numbers together, and all the variables

-34x-267=0

We move all terms containing x to the left, all other terms to the right

-34x=267

x=267/-34

x=-7+29/34

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