9(3x-11)=21(x-5)

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Solution for 9(3x-11)=21(x-5) equation: 



9(3x-11)=21(x-5)

We move all terms to the left:

9(3x-11)-(21(x-5))=0

We multiply parentheses

27x-(21(x-5))-99=0



We calculate terms in parentheses: -(21(x-5)), so:

21(x-5)

We multiply parentheses

21x-105

Back to the equation:

-(21x-105)



We get rid of parentheses

27x-21x+105-99=0

We add all the numbers together, and all the variables

6x+6=0

We move all terms containing x to the left, all other terms to the right

6x=-6

x=-6/6

x=-1

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