9(3x-2)-4(3x-2)=15+10(3x-2)

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Solution for 9(3x-2)-4(3x-2)=15+10(3x-2) equation: 



9(3x-2)-4(3x-2)=15+10(3x-2)

We move all terms to the left:

9(3x-2)-4(3x-2)-(15+10(3x-2))=0

We multiply parentheses

27x-12x-(15+10(3x-2))-18+8=0



We calculate terms in parentheses: -(15+10(3x-2)), so:

15+10(3x-2)

determiningTheFunctionDomain
10(3x-2)+15

We multiply parentheses

30x-20+15

We add all the numbers together, and all the variables

30x-5

Back to the equation:

-(30x-5)



We add all the numbers together, and all the variables

15x-(30x-5)-10=0

We get rid of parentheses

15x-30x+5-10=0

We add all the numbers together, and all the variables

-15x-5=0

We move all terms containing x to the left, all other terms to the right

-15x=5

x=5/-15

x=-1/3

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