9(3x-2)-6x=39(3x-2)-6x=3

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Solution for 9(3x-2)-6x=39(3x-2)-6x=3 equation: 



9(3x-2)-6x=39(3x-2)-6x=3

We move all terms to the left:

9(3x-2)-6x-(39(3x-2)-6x)=0

We add all the numbers together, and all the variables

-6x+9(3x-2)-(39(3x-2)-6x)=0

We multiply parentheses

-6x+27x-(39(3x-2)-6x)-18=0



We calculate terms in parentheses: -(39(3x-2)-6x), so:

39(3x-2)-6x

We add all the numbers together, and all the variables

-6x+39(3x-2)

We multiply parentheses

-6x+117x-78

We add all the numbers together, and all the variables

111x-78

Back to the equation:

-(111x-78)



We add all the numbers together, and all the variables

21x-(111x-78)-18=0

We get rid of parentheses

21x-111x+78-18=0

We add all the numbers together, and all the variables

-90x+60=0

We move all terms containing x to the left, all other terms to the right

-90x=-60

x=-60/-90

x=2/3

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