9(3x-2)=8(2x+6)

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Solution for 9(3x-2)=8(2x+6) equation: 



9(3x-2)=8(2x+6)

We move all terms to the left:

9(3x-2)-(8(2x+6))=0

We multiply parentheses

27x-(8(2x+6))-18=0



We calculate terms in parentheses: -(8(2x+6)), so:

8(2x+6)

We multiply parentheses

16x+48

Back to the equation:

-(16x+48)



We get rid of parentheses

27x-16x-48-18=0

We add all the numbers together, and all the variables

11x-66=0

We move all terms containing x to the left, all other terms to the right

11x=66

x=66/11

x=6

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