9(3x-4)=32-2x

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Solution for 9(3x-4)=32-2x equation: 



9(3x-4)=32-2x

We move all terms to the left:

9(3x-4)-(32-2x)=0

We add all the numbers together, and all the variables

9(3x-4)-(-2x+32)=0

We multiply parentheses

27x-(-2x+32)-36=0

We get rid of parentheses

27x+2x-32-36=0

We add all the numbers together, and all the variables

29x-68=0

We move all terms containing x to the left, all other terms to the right

29x=68

x=68/29

x=2+10/29

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