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9(3x-5)=5(2x+1)
We move all terms to the left:
9(3x-5)-(5(2x+1))=0
We multiply parentheses
27x-(5(2x+1))-45=0
We calculate terms in parentheses: -(5(2x+1)), so:We get rid of parentheses
5(2x+1)
We multiply parentheses
10x+5
Back to the equation:
-(10x+5)
27x-10x-5-45=0
We add all the numbers together, and all the variables
17x-50=0
We move all terms containing x to the left, all other terms to the right
17x=50
x=50/17
x=2+16/17
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