9(3y+3)=15(3y-9)+24

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Solution for 9(3y+3)=15(3y-9)+24 equation: 



9(3y+3)=15(3y-9)+24

We move all terms to the left:

9(3y+3)-(15(3y-9)+24)=0

We multiply parentheses

27y-(15(3y-9)+24)+27=0



We calculate terms in parentheses: -(15(3y-9)+24), so:

15(3y-9)+24

We multiply parentheses

45y-135+24

We add all the numbers together, and all the variables

45y-111

Back to the equation:

-(45y-111)



We get rid of parentheses

27y-45y+111+27=0

We add all the numbers together, and all the variables

-18y+138=0

We move all terms containing y to the left, all other terms to the right

-18y=-138

y=-138/-18

y=7+2/3

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