9(3z-5)=11(2z+5)

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Solution for 9(3z-5)=11(2z+5) equation:



9(3z-5)=11(2z+5)
We move all terms to the left:
9(3z-5)-(11(2z+5))=0
We multiply parentheses
27z-(11(2z+5))-45=0
We calculate terms in parentheses: -(11(2z+5)), so:
11(2z+5)
We multiply parentheses
22z+55
Back to the equation:
-(22z+55)
We get rid of parentheses
27z-22z-55-45=0
We add all the numbers together, and all the variables
5z-100=0
We move all terms containing z to the left, all other terms to the right
5z=100
z=100/5
z=20

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