9(3z-7)=18+18z

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Solution for 9(3z-7)=18+18z equation:



9(3z-7)=18+18z
We move all terms to the left:
9(3z-7)-(18+18z)=0
We add all the numbers together, and all the variables
9(3z-7)-(18z+18)=0
We multiply parentheses
27z-(18z+18)-63=0
We get rid of parentheses
27z-18z-18-63=0
We add all the numbers together, and all the variables
9z-81=0
We move all terms containing z to the left, all other terms to the right
9z=81
z=81/9
z=9

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