9(4-x)+7(x+6)=10-4(6+2x)

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Solution for 9(4-x)+7(x+6)=10-4(6+2x) equation: 



9(4-x)+7(x+6)=10-4(6+2x)

We move all terms to the left:

9(4-x)+7(x+6)-(10-4(6+2x))=0

We add all the numbers together, and all the variables

9(-1x+4)+7(x+6)-(10-4(2x+6))=0

We multiply parentheses

-9x+7x-(10-4(2x+6))+36+42=0



We calculate terms in parentheses: -(10-4(2x+6)), so:

10-4(2x+6)

determiningTheFunctionDomain
-4(2x+6)+10

We multiply parentheses

-8x-24+10

We add all the numbers together, and all the variables

-8x-14

Back to the equation:

-(-8x-14)



We add all the numbers together, and all the variables

-2x-(-8x-14)+78=0

We get rid of parentheses

-2x+8x+14+78=0

We add all the numbers together, and all the variables

6x+92=0

We move all terms containing x to the left, all other terms to the right

6x=-92

x=-92/6

x=-15+1/3

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