9(4x-5)+7(2+x)=227

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Solution for 9(4x-5)+7(2+x)=227 equation: 



9(4x-5)+7(2+x)=227

We move all terms to the left:

9(4x-5)+7(2+x)-(227)=0

We add all the numbers together, and all the variables

9(4x-5)+7(x+2)-227=0

We multiply parentheses

36x+7x-45+14-227=0

We add all the numbers together, and all the variables

43x-258=0

We move all terms containing x to the left, all other terms to the right

43x=258

x=258/43

x=6

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