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9(5-3x=(1/2)(x+4)
We move all terms to the left:
9(5-3x-((1/2)(x+4))=0
Domain of the equation: 2)(x+4))!=0We add all the numbers together, and all the variables
x∈R
9(5-3x-((+1/2)(x+4))=0
We multiply parentheses ..
9(5-3x-((+x^2+1/2*4))=0
We multiply all the terms by the denominator
9(5-3x-((+x^2+1=0
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