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9(5q+6)q=1
We move all terms to the left:
9(5q+6)q-(1)=0
We multiply parentheses
45q^2+54q-1=0
a = 45; b = 54; c = -1;
Δ = b2-4ac
Δ = 542-4·45·(-1)
Δ = 3096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3096}=\sqrt{36*86}=\sqrt{36}*\sqrt{86}=6\sqrt{86}$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-6\sqrt{86}}{2*45}=\frac{-54-6\sqrt{86}}{90} $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+6\sqrt{86}}{2*45}=\frac{-54+6\sqrt{86}}{90} $
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