9(6-2z)=-12(z-8)

Solution for 9(6-2z)=-12(z-8) equation:

9(6-2z)=-12(z-8)

We move all terms to the left:

9(6-2z)-(-12(z-8))=0

We add all the numbers together, and all the variables

9(-2z+6)-(-12(z-8))=0

We multiply parentheses

-18z-(-12(z-8))+54=0


We calculate terms in parentheses: -(-12(z-8)), so:

-12(z-8)

We multiply parentheses

-12z+96

Back to the equation:

-(-12z+96)


We get rid of parentheses

-18z+12z-96+54=0

We add all the numbers together, and all the variables

-6z-42=0

We move all terms containing z to the left, all other terms to the right

-6z=42

z=42/-6

z=-7