9(6k-18)=10(3+3k)=

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Solution for 9(6k-18)=10(3+3k)= equation: 



9(6k-18)=10(3+3k)=

We move all terms to the left:

9(6k-18)-(10(3+3k))=0

We add all the numbers together, and all the variables

9(6k-18)-(10(3k+3))=0

We multiply parentheses

54k-(10(3k+3))-162=0



We calculate terms in parentheses: -(10(3k+3)), so:

10(3k+3)

We multiply parentheses

30k+30

Back to the equation:

-(30k+30)



We get rid of parentheses

54k-30k-30-162=0

We add all the numbers together, and all the variables

24k-192=0

We move all terms containing k to the left, all other terms to the right

24k=192

k=192/24

k=8

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