9(8x+3)=28(10-x)

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Solution for 9(8x+3)=28(10-x) equation:



9(8x+3)=28(10-x)
We move all terms to the left:
9(8x+3)-(28(10-x))=0
We add all the numbers together, and all the variables
9(8x+3)-(28(-1x+10))=0
We multiply parentheses
72x-(28(-1x+10))+27=0
We calculate terms in parentheses: -(28(-1x+10)), so:
28(-1x+10)
We multiply parentheses
-28x+280
Back to the equation:
-(-28x+280)
We get rid of parentheses
72x+28x-280+27=0
We add all the numbers together, and all the variables
100x-253=0
We move all terms containing x to the left, all other terms to the right
100x=253
x=253/100
x=2+53/100

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