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9(9+20)=(x-2)(x+6)
We move all terms to the left:
9(9+20)-((x-2)(x+6))=0
We add all the numbers together, and all the variables
-((x-2)(x+6))+929=0
We multiply parentheses ..
-((+x^2+6x-2x-12))+929=0
We calculate terms in parentheses: -((+x^2+6x-2x-12)), so:We get rid of parentheses
(+x^2+6x-2x-12)
We get rid of parentheses
x^2+6x-2x-12
We add all the numbers together, and all the variables
x^2+4x-12
Back to the equation:
-(x^2+4x-12)
-x^2-4x+12+929=0
We add all the numbers together, and all the variables
-1x^2-4x+941=0
a = -1; b = -4; c = +941;
Δ = b2-4ac
Δ = -42-4·(-1)·941
Δ = 3780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3780}=\sqrt{36*105}=\sqrt{36}*\sqrt{105}=6\sqrt{105}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-6\sqrt{105}}{2*-1}=\frac{4-6\sqrt{105}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+6\sqrt{105}}{2*-1}=\frac{4+6\sqrt{105}}{-2} $
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