9(C+1)-3C=2(3C+1)-8

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Solution for 9(C+1)-3C=2(3C+1)-8 equation:


Simplifying
9(C + 1) + -3C = 2(3C + 1) + -8

Reorder the terms:
9(1 + C) + -3C = 2(3C + 1) + -8
(1 * 9 + C * 9) + -3C = 2(3C + 1) + -8
(9 + 9C) + -3C = 2(3C + 1) + -8

Combine like terms: 9C + -3C = 6C
9 + 6C = 2(3C + 1) + -8

Reorder the terms:
9 + 6C = 2(1 + 3C) + -8
9 + 6C = (1 * 2 + 3C * 2) + -8
9 + 6C = (2 + 6C) + -8

Reorder the terms:
9 + 6C = 2 + -8 + 6C

Combine like terms: 2 + -8 = -6
9 + 6C = -6 + 6C

Add '-6C' to each side of the equation.
9 + 6C + -6C = -6 + 6C + -6C

Combine like terms: 6C + -6C = 0
9 + 0 = -6 + 6C + -6C
9 = -6 + 6C + -6C

Combine like terms: 6C + -6C = 0
9 = -6 + 0
9 = -6

Solving
9 = -6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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