9(a+1)(a+2)=0

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Solution for 9(a+1)(a+2)=0 equation:


Simplifying
9(a + 1)(a + 2) = 0

Reorder the terms:
9(1 + a)(a + 2) = 0

Reorder the terms:
9(1 + a)(2 + a) = 0

Multiply (1 + a) * (2 + a)
9(1(2 + a) + a(2 + a)) = 0
9((2 * 1 + a * 1) + a(2 + a)) = 0
9((2 + 1a) + a(2 + a)) = 0
9(2 + 1a + (2 * a + a * a)) = 0
9(2 + 1a + (2a + a2)) = 0

Combine like terms: 1a + 2a = 3a
9(2 + 3a + a2) = 0
(2 * 9 + 3a * 9 + a2 * 9) = 0
(18 + 27a + 9a2) = 0

Solving
18 + 27a + 9a2 = 0

Solving for variable 'a'.

Factor out the Greatest Common Factor (GCF), '9'.
9(2 + 3a + a2) = 0

Factor a trinomial.
9((2 + a)(1 + a)) = 0

Ignore the factor 9.

Subproblem 1

Set the factor '(2 + a)' equal to zero and attempt to solve: Simplifying 2 + a = 0 Solving 2 + a = 0 Move all terms containing a to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + a = 0 + -2 Combine like terms: 2 + -2 = 0 0 + a = 0 + -2 a = 0 + -2 Combine like terms: 0 + -2 = -2 a = -2 Simplifying a = -2

Subproblem 2

Set the factor '(1 + a)' equal to zero and attempt to solve: Simplifying 1 + a = 0 Solving 1 + a = 0 Move all terms containing a to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + a = 0 + -1 Combine like terms: 1 + -1 = 0 0 + a = 0 + -1 a = 0 + -1 Combine like terms: 0 + -1 = -1 a = -1 Simplifying a = -1

Solution

a = {-2, -1}

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