9(a+1)=3(4a-5)

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Solution for 9(a+1)=3(4a-5) equation: 



9(a+1)=3(4a-5)

We move all terms to the left:

9(a+1)-(3(4a-5))=0

We multiply parentheses

9a-(3(4a-5))+9=0



We calculate terms in parentheses: -(3(4a-5)), so:

3(4a-5)

We multiply parentheses

12a-15

Back to the equation:

-(12a-15)



We get rid of parentheses

9a-12a+15+9=0

We add all the numbers together, and all the variables

-3a+24=0

We move all terms containing a to the left, all other terms to the right

-3a=-24

a=-24/-3

a=+8

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