9(a-2)-4(a+5)=-7(a+9)+13(a-7)

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Solution for 9(a-2)-4(a+5)=-7(a+9)+13(a-7) equation: 



9(a-2)-4(a+5)=-7(a+9)+13(a-7)

We move all terms to the left:

9(a-2)-4(a+5)-(-7(a+9)+13(a-7))=0

We multiply parentheses

9a-4a-(-7(a+9)+13(a-7))-18-20=0



We calculate terms in parentheses: -(-7(a+9)+13(a-7)), so:

-7(a+9)+13(a-7)

We multiply parentheses

-7a+13a-63-91

We add all the numbers together, and all the variables

6a-154

Back to the equation:

-(6a-154)



We add all the numbers together, and all the variables

5a-(6a-154)-38=0

We get rid of parentheses

5a-6a+154-38=0

We add all the numbers together, and all the variables

-1a+116=0

We move all terms containing a to the left, all other terms to the right

-a=-116

a=-116/-1

a=+116

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