9(a-4)+3(2a+5)=7(3a-4)-6a+7

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Solution for 9(a-4)+3(2a+5)=7(3a-4)-6a+7 equation: 



9(a-4)+3(2a+5)=7(3a-4)-6a+7

We move all terms to the left:

9(a-4)+3(2a+5)-(7(3a-4)-6a+7)=0

We multiply parentheses

9a+6a-(7(3a-4)-6a+7)-36+15=0



We calculate terms in parentheses: -(7(3a-4)-6a+7), so:

7(3a-4)-6a+7

We add all the numbers together, and all the variables

-6a+7(3a-4)+7

We multiply parentheses

-6a+21a-28+7

We add all the numbers together, and all the variables

15a-21

Back to the equation:

-(15a-21)



We add all the numbers together, and all the variables

15a-(15a-21)-21=0

We get rid of parentheses

15a-15a+21-21=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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