9(b+2)=5-(-9b-13)

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Solution for 9(b+2)=5-(-9b-13) equation: 



9(b+2)=5-(-9b-13)

We move all terms to the left:

9(b+2)-(5-(-9b-13))=0

We multiply parentheses

9b-(5-(-9b-13))+18=0



We calculate terms in parentheses: -(5-(-9b-13)), so:

5-(-9b-13)

determiningTheFunctionDomain
-(-9b-13)+5

We get rid of parentheses

9b+13+5

We add all the numbers together, and all the variables

9b+18

Back to the equation:

-(9b+18)



We get rid of parentheses

9b-9b-18+18=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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