9(b-4)-7b=5(3b+1)

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Solution for 9(b-4)-7b=5(3b+1) equation: 



9(b-4)-7b=5(3b+1)

We move all terms to the left:

9(b-4)-7b-(5(3b+1))=0

We add all the numbers together, and all the variables

-7b+9(b-4)-(5(3b+1))=0

We multiply parentheses

-7b+9b-(5(3b+1))-36=0



We calculate terms in parentheses: -(5(3b+1)), so:

5(3b+1)

We multiply parentheses

15b+5

Back to the equation:

-(15b+5)



We add all the numbers together, and all the variables

2b-(15b+5)-36=0

We get rid of parentheses

2b-15b-5-36=0

We add all the numbers together, and all the variables

-13b-41=0

We move all terms containing b to the left, all other terms to the right

-13b=41

b=41/-13

b=-3+2/13

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