9(b-4)-7b=5(3b+2)

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Solution for 9(b-4)-7b=5(3b+2) equation:



9(b-4)-7b=5(3b+2)
We move all terms to the left:
9(b-4)-7b-(5(3b+2))=0
We add all the numbers together, and all the variables
-7b+9(b-4)-(5(3b+2))=0
We multiply parentheses
-7b+9b-(5(3b+2))-36=0
We calculate terms in parentheses: -(5(3b+2)), so:
5(3b+2)
We multiply parentheses
15b+10
Back to the equation:
-(15b+10)
We add all the numbers together, and all the variables
2b-(15b+10)-36=0
We get rid of parentheses
2b-15b-10-36=0
We add all the numbers together, and all the variables
-13b-46=0
We move all terms containing b to the left, all other terms to the right
-13b=46
b=46/-13
b=-3+7/13

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