9(b-5)=6(b-2)

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Solution for 9(b-5)=6(b-2) equation: 



9(b-5)=6(b-2)

We move all terms to the left:

9(b-5)-(6(b-2))=0

We multiply parentheses

9b-(6(b-2))-45=0



We calculate terms in parentheses: -(6(b-2)), so:

6(b-2)

We multiply parentheses

6b-12

Back to the equation:

-(6b-12)



We get rid of parentheses

9b-6b+12-45=0

We add all the numbers together, and all the variables

3b-33=0

We move all terms containing b to the left, all other terms to the right

3b=33

b=33/3

b=11

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