9(c+2)-11=5(2c+3)-2

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Solution for 9(c+2)-11=5(2c+3)-2 equation:


Simplifying
9(c + 2) + -11 = 5(2c + 3) + -2

Reorder the terms:
9(2 + c) + -11 = 5(2c + 3) + -2
(2 * 9 + c * 9) + -11 = 5(2c + 3) + -2
(18 + 9c) + -11 = 5(2c + 3) + -2

Reorder the terms:
18 + -11 + 9c = 5(2c + 3) + -2

Combine like terms: 18 + -11 = 7
7 + 9c = 5(2c + 3) + -2

Reorder the terms:
7 + 9c = 5(3 + 2c) + -2
7 + 9c = (3 * 5 + 2c * 5) + -2
7 + 9c = (15 + 10c) + -2

Reorder the terms:
7 + 9c = 15 + -2 + 10c

Combine like terms: 15 + -2 = 13
7 + 9c = 13 + 10c

Solving
7 + 9c = 13 + 10c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-10c' to each side of the equation.
7 + 9c + -10c = 13 + 10c + -10c

Combine like terms: 9c + -10c = -1c
7 + -1c = 13 + 10c + -10c

Combine like terms: 10c + -10c = 0
7 + -1c = 13 + 0
7 + -1c = 13

Add '-7' to each side of the equation.
7 + -7 + -1c = 13 + -7

Combine like terms: 7 + -7 = 0
0 + -1c = 13 + -7
-1c = 13 + -7

Combine like terms: 13 + -7 = 6
-1c = 6

Divide each side by '-1'.
c = -6

Simplifying
c = -6

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